I am thinking of four consecutive integers. The sum of the squares of the second and third numbers is 61. Find all four of the integers.

unknown values: x,x+1,x+2,x+3

equation: (x+1)^2+(x+2)^2=61

answer: 4; 5; 6; 7 or -7; -6; -5; -4

find three consecutive integers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third

unknown values: x-1,x,x+1

equation: 2*(x-1)+4*x=2*(x+1)+20

answer: 5; 6; 7

The tens digits of a two-digit number is 2 less than the units digit. The sum of the digits is 12. Identify what the number is.

unknown values: x+10*y

equation: y=x-2

equation: x+y=12

answer: 57

The smallest of three consecutive integers is 18 less than the sum of the two larger integers. Find the integers

unknown values: x-1,x,x+1

equation: x-1=(x+(x+1))-18

answer: 15; 16; 17

The square of the first of three consecutive odd integers is 9 more than 6 times the sum of the second and the first. Find the numbers.

unknown values: x,x+2,x+4

equation: x^2-9=6(x+2+x)

answer: ans_no_result

find three consecutive integers such that the sum of the second and the third is eighty-eight more than one-third the smallest

unknown values: x-1,x,x+1

equation: x+(x+1)=(1/3)*(x-1)+88

answer: 51; 52; 53

find three consecutive integers such that the sum of the second and third is forty eight more than one-fifth the smallest.

unknown values: x-1,x,x+1

equation: x+(x+1)=(x-1)*1/5+48

answer: 25; 26; 27

Find two consecutive integers whose product is 6 less than the square of the larger number.

unknown values: x, x+1

equation: x(x+1)+6=(x+1)^2

answer: 5; 6

two consecutive odd integers, the sum of three times the smaller and the larger is fourteen

unknown values: 2*k-1,2*k+1

equation: 3*(2*k-1)+(2*k+1)=14

answer: 3; 5

Find two consecutive odd integers such that the larger, added to eight times the smaller, equals 119.

unknown values: 2*k-1,2*k+1

equation: (2*k+1)+8*(2*k-1)=119

answer: 13; 15