Find four consecutive multiples of five such that twice the sum of the two biggest exceeds twice the smallest by ten.

unknown values: 5*(k-1),5*k,5*(k+1),5*(k+2)

equation: 2*(5*(k+1)+5*(k+2))-2*(5*(k-1))=10

answer: -20; -15; -10; -5

find 3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two.

unknown values: x-1,x,x+1

equation: 4*(x-1)=(x+(x+1))+7

answer: 5; 6; 7

the sum of two numbers is 10 and the sum of their reciprocals is 5/12. find the numbers.

unknown values: x,y

equation: x + y = 10

equation: 1/x + 1/y = 5/12

answer: {4; 6}

find three consecutive even integers so that the largest is 2 times more than the smallest

unknown values: 2*k-2,2*k,2*k+2

equation: 2*k+2=(2*k-2)+2*(2*k-2)

answer: 2; 4; 6

find two consecutive even integers if one-third of the smaller one is equal to one-fourth of the larger one

unknown values: 2*k,2*k+2

equation: (1/3)*(2*k)=(1/4)*(2*k+2)

answer: 6; 8

five consecutive odd integers whose sum is 85

unknown values: 2*k-3,2*k-1,2*k+1,2*k+3,2*k+5

equation: (2*k-3)+(2*k-1)+(2*k+1)+(2*k+3)+(2*k+5)=85

answer: 13; 15; 17; 19; 21

Find five consecutive odd numbers that have a sum of 65.

unknown values: 2*k-3,2*k-1,2*k+1,2*k+3,2*k+5

equation: (2*k-3)+(2*k-1)+(2*k+1)+(2*k+3)+(2*k+5)=65

answer: 9; 11; 13; 15; 17

Find the largest of four consecutive odd integers such that the sum of the first and the fourth is 27 less than three times the first integer.

unknown values: 2*k+3

equation: (2*k-3)+(2*k+3)=3*(2*k-3)-27

answer: 39

if a number is added to its square, the result is 56. Find the number

unknown values: n

equation: n^2 + n = 56

answer: 7 or -8

The sum of an integer and its square is 30. Find the number?

unknown values: x

equation: x + x^2 = 30

answer: 5 or -6