Matthias has 40 soccer balls and 15 basketballs. 30 soccer balls and 7 basketballs have a hole in them. How many balls in total does Matthias have without holes in them?

Matthias has 40-30 =

<<40-30=10>>10 soccer balls without holes. Matthias has 15-7 = <<15-7=8>>8 basketballs without holes. A total of 10+8 = <<10+8=18>>18 balls do not have holes. #### 18 Jenny is scraping gum off the bottom of the seats in a stadium with two sections. Section A has 1 subsection with 60 seats and 3 subsections with 80 seats each. Section B has 20 more seats than 3 times as many seats as Section A has total. How many seats does Section B have? First find how many total seats are in the 80-seat subsections: 80 seats/subsection * 3 subsections = 240 seats Then add the number of seats in the 60-seat section to find the total number of seats in Section A: 240 seats + 60 seats = <<240+60=300>>300 seats Then triple that number: 300 seats * 3 = <<300*3=900>>900 seats Then add 20 seats to find the total number of seats in Section B: 900 seats + 20 seats = <<900+20=920>>920 seats #### 920 The running time of Beast of War: Armoured Command is 10 minutes longer than that of Alpha Epsilon, which is 30 minutes shorter than that of Millennium. If Millennium runs for 2 hours, what is the running time of Beast of War: Armoured Command in minutes? One hour contains 60 minutes so 2 hours contain 60*2 = <<2*60=120>>120 minutes Alpha Epsilon's running time is 30 minutes less than that of Millennium (which runs for 120 minutes) hence 120-30 = <<120-30=90>>90 minutes Beast of War: Armoured Command runs for 10 minutes more than Alpha Epsilon hence 90+10 = <<10+90=100>>100 minutes #### 100 A packet of candy sweets has 30 cherry-flavored sweets, 40 strawberry-flavored sweets, and 50 pineapple-flavored sweets. Aaron eats half of each of the flavored sweets and gives 5 cherry-flavored sweets to his friend. How many sweets are still in the packet of candy? Aaron eats 1/2*30 sweets + 1/2*40 sweets + 1/2*50 sweets = <<1/2*30+1/2*40+1/2*50=60>>60 candy sweets. The packet of candy sweets still has 60 sweets - 5 sweets = <<60-5=55>>55 candy sweets. #### 55 Oliver has two bags of vegetables. Each bag weighs 1/6 as much as James’s bag, which weighs 18kg. What is the combined weight of both Oliver’s bags? Each of Oliver’s bags weighs 18 kg * 1/6 =<<18*1/6=3>>3 kg. Combined, both his bags weigh 3 kg * 2 = <<3*2=6>>6 kg. #### 6 Greg's PPO algorithm obtained 90% of the possible reward on the CoinRun environment. CoinRun's maximum reward is half as much as the maximum ProcGen reward of 240. How much reward did Greg's PPO algorithm get? Half of much as ProcGen's maximum reward is 240/2=<<240/2=120>>120 reward 90% of CoinRun's maximum reward is 120*.9=<<120*.9=108>>108 reward #### 108 Julia has a parrot and a rabbit. She buys food for both of the animals for $30 in total a week. Julia has the rabbit for 5 weeks, and the parrot for 3 weeks. How much money did Julia already spend on food for her animals, if the weekly cost of the rabbit food is $12? If the rabbit food costs $12 a week, then the parrot food costs $30 - $12 = $18 a week. Julia has the parrot for 3 weeks, so she spent 3 weeks * $18/week = $<<3*18=54>>54 on her. The rabbit is her only for 5 weeks, so she spent 5 weeks * $12/week = $<<5*12=60>>60 on him. In total, Julia spent $54 + $60 = $<<54+60=114>>114 on food for her animals. #### 114 Janet has 60 less than four times as many siblings as Masud. Carlos has 3/4 times as many siblings as Masud. If Masud has 60 siblings, how many more siblings does Janet have more than Carlos? If Masud has 60 siblings, and Carlos has 3/4 times as many siblings as Masud, Carlos has 3/4*60=<<60*3/4=45>>45 siblings. Four times as many siblings as Masud has is 4*60=<<4*60=240>>240 Janet has 60 less than four times as many siblings as Masud, a total of 240-60=<<240-60=180>>180 siblings. The number of siblings Janet have more than Carlos is 180-45=<<180-45=135>>135 #### 135 A highway is being extended from its current length of 200 miles up to 650 miles. 50 miles are built on the first day, and three times this amount are built on the second day. How many miles still need to be added to the highway to finish extending it? The length of the highway that needs to be constructed is 650 – 200 = <<650-200=450>>450 miles. After the first day, there are still 450 – 50 = <<450-50=400>>400 miles that need to be constructed. On the second day, 50 miles * 3 = <<50*3=150>>150 miles are added to the highway. This means that 400 – 150 = <<400-150=250>>250 miles still need to be added to the highway. #### 250 Susan is making jewelry with a repeating pattern that has 3 green beads, 5 purple beads, and twice as many red beads as green beads. If the pattern repeats three times per bracelet and 5 times per necklace, how many beads does she need to make 1 bracelets and 10 necklaces? First find the number of red beads per repeat: 3 green * 2 red/green = <<3*2=6>>6 red Then add the number of beads of each color to find the total number of bead per repeat: 6 beads + 3 beads + 5 beads = <<6+3+5=14>>14 beads Then multiply the number of beads per repeat by the number of repeats per bracelet to find the number of beads per bracelet: 14 beads/repeat * 3 repeats/bracelet = <<14*3=42>>42 beads/bracelet Then multiply the number of beads per repeat by the number of repeats per necklace to find the number of beads per necklace: 14 beads/repeat * 5 repeats/necklace = <<14*5=70>>70 beads/necklace Then multiply the number of beads per necklace by the number of necklaces to find the total number of beads used in the necklaces: 70 beads/necklace * 10 necklaces = <<70*10=700>>700 beads Then add the number of beads used in a bracelet to the number of beads in the necklaces to find the total number of beads used: 700 beads + 42 beads = <<700+42=742>>742 beads #### 742