When one-half of a number is added to one-fourth of the number, the sum is twenty-one. What is the number?

unknown values: n

equation: (1/2) * n + (1/4) * n = 21

answer: 28

a number is 110 less than its square. find all such numbers.

unknown values: n

equation: n = n^2 - 110

answer: -10 or 11

Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.

unknown values: k,k+1,k+2

equation: k(k+1) = (k+2)^2 - 19

answer: 5; 6; 7

if the difference between the smallest and the largest of five consecutive odd numbers is t, what is t-2

unknown values: t-2

equation: (2*k+9) - (2*k+1) = t

answer: 6

find five consecutive odd integers such that the sum of the first and fifth is one less than three times the fourth

unknown values: 2*k+1,2*k+3,2*k+5,2*k+7,2*k+9

equation: (2*k+1) + (2*k+9) = 3(2*k+7) - 1

answer: -9; -7; -5; -3; -1

find 5 consecutive odd integers such that the sum of the first and fifth is one less than three times the fourth

unknown values: 2*k+1,2*k+3,2*k+5,2*k+7,2*k+9

equation: (2*k+1)+(2*k+9) = 3(2*k+7)-1

answer: -9; -7; -5; -3; -1

Find four consecutive even integers such that the sum of the second and fourth be 74.

unknown values: 2*k,2*k+2,2*k+4,2*k+6

equation: (2*k+2)+(2*k+6)=74

answer: ans_no_result

what 5 consecutive odd numbers total 95

unknown values: 2*k+1,2*k+3,2*k+5,2*k+7,2*k+9

equation: (2*k+1)+(2*k+3)+(2*k+5)+(2*k+7)+(2*k+9) = 95

answer: 15; 17; 19; 21; 23

Find 3 consecutive odd integers such that 3 times the 2nd minus the 3rd is 31 more than the first.

unknown values: 2*k+1,2*k+3,2*k+5

equation: 3(2*k+3)-(2*k+5) = 31 + (2*k+1)

answer: 29; 31; 33

i am a number that is greater than 81 but less than 95. the sum of my digits is 15. what number am i?

unknown values: n

equation: 10*a + b = n

equation: a+b=15

answer: 87