When one-half of a number is added to one-fourth of the number, the sum is twenty-one. What is the number?
unknown values: n
equation: (1/2) * n + (1/4) * n = 21
answer: 28
a number is 110 less than its square. find all such numbers.
unknown values: n
equation: n = n^2 - 110
answer: -10 or 11
Find 3 consecutive numbers where the product of the smaller two numbers is 19 less than the square of the largest number.
unknown values: k,k+1,k+2
equation: k(k+1) = (k+2)^2 - 19
answer: 5; 6; 7
if the difference between the smallest and the largest of five consecutive odd numbers is t, what is t-2
unknown values: t-2
equation: (2*k+9) - (2*k+1) = t
answer: 6
find five consecutive odd integers such that the sum of the first and fifth is one less than three times the fourth
unknown values: 2*k+1,2*k+3,2*k+5,2*k+7,2*k+9
equation: (2*k+1) + (2*k+9) = 3(2*k+7) - 1
answer: -9; -7; -5; -3; -1
find 5 consecutive odd integers such that the sum of the first and fifth is one less than three times the fourth
unknown values: 2*k+1,2*k+3,2*k+5,2*k+7,2*k+9
equation: (2*k+1)+(2*k+9) = 3(2*k+7)-1
answer: -9; -7; -5; -3; -1
Find four consecutive even integers such that the sum of the second and fourth be 74.
unknown values: 2*k,2*k+2,2*k+4,2*k+6
equation: (2*k+2)+(2*k+6)=74
answer: ans_no_result
what 5 consecutive odd numbers total 95
unknown values: 2*k+1,2*k+3,2*k+5,2*k+7,2*k+9
equation: (2*k+1)+(2*k+3)+(2*k+5)+(2*k+7)+(2*k+9) = 95
answer: 15; 17; 19; 21; 23
Find 3 consecutive odd integers such that 3 times the 2nd minus the 3rd is 31 more than the first.
unknown values: 2*k+1,2*k+3,2*k+5
equation: 3(2*k+3)-(2*k+5) = 31 + (2*k+1)
answer: 29; 31; 33
i am a number that is greater than 81 but less than 95. the sum of my digits is 15. what number am i?
unknown values: n
equation: 10*a + b = n
equation: a+b=15
answer: 87