One number is 12 more than another number. The sum of twice the larger number and three times the smaller number is 64. Find the numbers.

One number is 12 more than another number. The sum of twice the larger number and three times the smaller number is 64. Find the numbers.

unknown values: m,n

equation: m = n + 12

equation: 2*m + 3*n = 64

answer: {20; 8}

find a six-digit number in which the first is two less that the fifth, the second digit is one more that the fourth, and the fifth digit is four less than the last. The sum of the third and last digits equals the second and the sum of all the digits is 30.

unknown values: n

equation: n = 100000*a + 10000*b + 1000*c + 100*d + 10*t + f

equation: a=t-2

equation: b=d+1

equation: t=f-4

equation: c+f=b

equation: a+b+c+d+t+f=30

answer: 192837

a+b=10.6a+c=8.5b+c=8.1how much are a, b, c worth?

unknown values: a,b,c

equation: a+b=10.6

equation: a+c=8.5

equation: b+c=8.1

answer: a = 5.5; b = 5.1; c = 3 | a = 11/2; b = 51/10; c = 3 | 11/2; 51/10; 3 | 5.5; 5.1; 3

The sum of two consecutive odd numbers is 32. What is the product of the two numbers?

unknown values: p

equation: p = (2*k+1)(2*k+3)

equation: (2*k+1)+(2*k+3)=32

answer: 255

One number is 6 less than a second number. Twice the second number is 48 more than 5 times the first. Find the two numbers

unknown values: x,y

equation: x = y-6

equation: 2*y = 5*x+48

answer: {-12;-6}

the sum of 3 digits is 5. The first and last digits are the same. If the middle digit is exchanged with the first digit , the new number is 90 less than the original number. Find the original number.

unknown values: n

equation: n=100*x+10*y+z

equation: x+y+z=5

equation: x=z

equation: 100*y+10*x+z=n-90

answer: 212

The sum of 3 numbers is 34. The first number is 3 less than the second and the third is 4 more than the second.

unknown values: x,y,z

equation: x+y+z=34

equation: x+3=y

equation: z=y+4

answer: {8;11;15}

The sum of squares of three consecutive odd numbers is 155. What are the numbers?

unknown values: 2*k+1,2*k+3,2*k+5

equation: (2*k+1)^2 + (2*k+3)^2 + (2*k+5)^2 = 155

answer: 5; 7; 9 or -9; -7; -5

one number is six more than another number. The sum of the larger number and twice the smaller number is 12. Find the numbers.

unknown values: x, y

equation: x = y + 6

equation: x + 2*y = 12

answer: 8; 2

One number is 8 more than another number. If the sum of the smaller number and twice the larger number is 46, find the two numbers.

unknown values: x, y

equation: x = y + 8

equation: y + 2*x = 46

answer: 18; 10