If 5 times a integer is subtracted from twice the square of the integer, the result is 63. Find the integer

unknown values: x

equation: 2*x^2-5*x=63

answer: 7

Three times the square of a positive number decreased by 20 times the number is 63. Find the number.

unknown values: x

equation: 3*x^2 - 20*x = 63

equation: x >0

answer: 9

find three consecutive integers whose sum is 11 more than twice the greatest of the three integers.

unknown values: x,x+1,x+2

equation: x + x+1 +x+2 = 11 + 2(x+2)

answer: 12;13;14

find three consecutive integers such that three times the middle integer is equal to the sum of five times the first and three times the third integer decreased by 13

unknown values: x,x+1,x+2

equation: 3(x+1)=5*x + 3(x+2) - 13

answer: 2;3;4

Find three consecutive even integers such that twice the sum of the first and third is twelve more than twice the second.

unknown values: x,x+2,x+4

equation: 2(x+x+4)=12+2(x+2)

answer: 4; 6; 8

Find three consecutive odd integers such that four times the sum of the first and second is 17 more than 7 times the third

unknown values: n,n+2,n+4

equation: 4(n+(n+2)) = 17 + 7(n+4)

answer: 37; 39; 41

find three consecutive positive odd integers such that the product of the second and third integers is 18 more than 9 times the first integer

unknown values: 2*k+1,2*k+3,2*k+5

equation: (2*k+3)*(2*k+5)=9*(2*k+1)+18

answer: 5;7;9

Find three consecutive positive even integers such that the sum of the squares of the first and second integers is equal to the square of the third integer plus 20.

unknown values: n,n+2,n+4

equation: n^2+(n+2)^2=(n+4)^2+20

equation: n=2*k

answer: 8;10;12

If four consecutive odd integers had a sum of 96, what would be the largest integer?

unknown values: n+6

equation: n + n+2 + n+4 + n+6 = 96

equation: n=2*k-1

answer: 27

Twelve more than one-half the square of a number is 30. What is the number?

unknown values: x

equation: x^2/2+12=30

answer: 6 or -6