twice the first of three consecutive even integers minus the third equals 36. Find the three integers.

unknown values: 2*x-2,2*x,2*x+2

equation: 2(2*x-2)-(2*x+2)= 36

answer: 40;42;44

three times the largest of three consecutive odd integers is three less than twice the sum of the other two integers. find the integers.

unknown values: 2*k-1,2*k+1,2*k+3

equation: 3*(2*k+3)=3+2*(2*k+1+2*k-1)

answer: 5;7;9

What are three consecutive odd integers so that five times the middle integer is nine more than twice the sum of the first and third integers?

unknown values: 2*k-1,2*k+1,2*k+3

equation: 5*(2*k+1)=2*((2*k-1)+(2*k+3))+9

answer: 7; 9; 11

find three consecutive odd integers such that five times the sum of the first and second is 1 less than 9 times the third

unknown values: 2*k-1,2*k+1,2*k+3

equation: 5*((2*k-1)+(2*k+1))=9*(2*k+3)-1

answer: 25; 27; 29

Find three consecutive odd integers such that three times the first integer is one less than the sum of the second and third integers

unknown values: 2*k-1,2*k+1,2*k+3

equation: 3*(2*k-1)=(2*k+1)+(2*k+3)-1

answer: 5; 7; 9

find three consecutive odd integers such that three times the smallest equals the sum of the other two integers decreased by 1?

unknown values: 2*n-1,2*n+1,2*n+3

equation: 3(2*n-1) = (2*n+1)+(2*n+3)-1

answer: 5; 7; 9

The smallest of three consecutive even integers is 4 less than 5 times the largest. Find the integers.

unknown values: 2*k-2,2*k,2*k+2

equation: 2*k-2=5*(2*k+2)-4

answer: -4; -2; 0

Three consecutive even integers are such that the difference of the smallest integer and twice the largest integer is 10. Find the three integers.

unknown values: 2*k-2,2*k,2*k+2

equation: 2*(2*k+2)-(2*k-2)=10

answer: 2; 4; 6 or -18; -16; -14 | 2; 4; 6 | -18; -16; -14

the larger of two consecutive odd integers is 7 greater than twice the smaller. Find the integers

unknown values: 2*k-1,2*k+1

equation: (2*k+1)=2*(2*k-1)+7

answer: -5; -3

The greater of two consecutive odd integers is eight more than three times the lesser

unknown values: 2*k-1,2*k+1

equation: 2*k+1=3*(2*k-1)+8

answer: -3; -1