the greater of two numbers is 9 more than the smaller. if the smaller is added to twice the greater the result is 22. find both numbers

unknown values: g,s

equation: g = 9 + s

equation: 2*g + s = 22

answer: {31/3; 4/3} | {10.333; 1.333}

One number plus twice another number gives a sum of 42. The difference of these same two numbers equals �C3.Find the two numbers

unknown values: a,b

equation: a + 2*b = 42

equation: a - b = -3

answer: {12; 15}

Find two positive numbers so that twice their sum equals their product and one number is 8 times the other number.

unknown values: x,y

equation: 2(x+y) = xy

equation: x = 8*y

answer: 18; 9/4 | 18; 2.25

The sum of 2 numbers is 25. 12 less than 4 times one of the numbers is 16 more than twice the other number. Find both numbers.

unknown values: x,y

equation: x+y=25

equation: 4*x - 12 = 16 + 2*y

answer: {12; 13}

the sum of two numbers is 25. 12 less than four times one of the numbers is 16 more than twice the other number

unknown values: x,y

equation: x+y=25

equation: 4*x-12=2*y+16

answer: {13; 12}

find three consecutive odd integers such that 3 times their sum is 5 more than 8 times the middle one

unknown values: 2*k-1,2*k+1,2*k+3

equation: 3*((2*k-1)+(2*k+1)+(2*k+3))=8*(2*k+1)+5

answer: 3; 5; 7

The sum of three consecutive odd integers is 40 more than the smallest. What are the integers?

unknown values: 2*n+1, 2*n+3, 2*n+5

equation: (2*n+1) + (2*n+3) + (2*n+5) = 40 + (2*n+1)

answer: 17; 19; 21

find three consecutive odd integers such that the sum of the first, twice the second, and three times the third is 94

unknown values: 2*k-1,2*k+1,2*k+3

equation: (2*k-1)+2*(2*k+1)+3*(2*k+3)=94

answer: 13; 15; 17

find four consecutive even numbers such that three-fourths of the sum of the second and fourth numbers equals the sum of the first and the third numbers.

unknown values: 2*k-2,2*k,2*k+2,2*k+4

equation: 3/4*(2*k+(2*k+4))=(2*k-2)+(2*k+2)

answer: 4; 6; 8; 10

What would be the four consecutive odd integers if the sum is -80.

unknown values: 2*k-3,2*k-1,2*k+1,2*k+3

equation: (2*k-3)+(2*k-1)+(2*k+1)+(2*k+3)=-80

answer: -23; -21; -19; -17