find two consecutive even integers such that three times the first equals twice the second

find two consecutive even integers such that three times the first equals twice the second

unknown values: 2*k,2*k+2

equation: 3*(2*k)=2*(2*k+2)

answer: 4; 6

Find two consecutive even integers such that eight times the first equals seven times the second.

unknown values: 2*k, 2*k+2

equation: 8(2*k)=7(2*k+2)

answer: 14; 16

Find two consecutive even integers such that nine times the smaller is equal to twelve times the larger.

unknown values: 2*k, 2*k+2

equation: 9(2*k)=12(2*k+2)

answer: -8; -6

the sum of three consecutive odd number is 87.find the first number

unknown values: 2*k-1

equation: (2*k-1)+(2*k+1)+(2*k+3)=87

answer: 27

The sum of 3 consecutive odd integers is 27. find the smallest of these integers.

unknown values: 2*k-1

equation: (2*k-1)+(2*k+1)+(2*k+3)=27

answer: 7

the sum of three consecutive odd numbers is 75 what are the smallest of these numbers

unknown values: 2*k-1

equation: (2*k-1)+(2*k+1)+(2*k+3)=75

answer: 23

If x is an odd number and the sum of x and two consecutive odd numbers after x is 57, find the value of x.

unknown values: 2*k-1

equation: (2*k-1)+(2*k+1)+(2*k+3)=57

answer: 17

if the first and third of three consecutive odd integers are added, the result is 87 less than five times the second integer. find the third integer

unknown values: 2*k+3

equation: (2*k-1)+(2*k+3)=5*(2*k+1)-87

answer: 31

If the first and third of three consecutive odd integers are added, the result is 81 less than five times the second integer. Find the third integers.

unknown values: 2*k+3

equation: (2*k-1)+(2*k+3)=5*(2*k+1)-81

answer: 29

One number is 1 more than another doubled. If their difference is 10, find the numbers.

unknown values: x,y

equation: x = 1 + 2*y

equation: x - y = 10

answer: 19; 9