When 60% of a number is added to the number, the result is 192. What is the number?

When 60% of a number is added to the number, the result is 192. What is the number?

unknown values: n

equation: 60/100*n + n = 192

answer: 120

the sum of three consecutive odd integers is five less than twice the smallest of these integers

unknown values: 2*k-1,2*k+1,2*k+3

equation: (2*k-1)+(2*k+1)+(2*k+3)=2*(2*k-1)-5

answer: -11; -9; -7

Find two consecutive integers whose sum is the square of 7.

unknown values: x,x+1

equation: x+(x+1)=7*7

answer: 24; 25

Find four consecutive even integers such that twice the sum of the first and fourth is 124

unknown values: 2*k-2,2*k,2*k+2,2*k+4

equation: 2*((2*k-2)+(2*k+4))=124

answer: 28; 30; 32; 34

What three consecutive integers have a sum of -186?

unknown values: x-1,x,x+1

equation: (x-1)+x+(x+1)=-186

answer: -63; -62; -61

Find three consecutive integers whose sum is -147

unknown values: x-1,x,x+1

equation: (x-1)+x+(x+1)=-147

answer: -50; -49; -48

Find four consecutive multiples of five such that twice the sum of the two biggest exceeds twice the smallest by ten.

unknown values: 5*(k-1),5*k,5*(k+1),5*(k+2)

equation: 2*(5*(k+1)+5*(k+2))-2*(5*(k-1))=10

answer: -20; -15; -10; -5

find 3 consecutive numbers such that 4 times the first is equal to 7 more than the sum of the other two.

unknown values: x-1,x,x+1

equation: 4*(x-1)=(x+(x+1))+7

answer: 5; 6; 7

find three consecutive even integers so that the largest is 2 times more than the smallest

unknown values: 2*k-2,2*k,2*k+2

equation: 2*k+2=(2*k-2)+2*(2*k-2)

answer: 2; 4; 6

five consecutive odd integers whose sum is 85

unknown values: 2*k-3,2*k-1,2*k+1,2*k+3,2*k+5

equation: (2*k-3)+(2*k-1)+(2*k+1)+(2*k+3)+(2*k+5)=85

answer: 13; 15; 17; 19; 21