To make room for a new inventory of books, Gordon's local bookstore is offering 30% off any book that is over $22.00 and 20% off any book under $20.00. He buys several books with the following prices; $25.00, $18.00, $21.00, $35.00, $12.00 and $10.00. How much will he spend on books?

He gets 30% off any book over $22 and he buys books that cost $25.00 and $35.00 so the total cost of these books is $25 + $35 = $

<<25+35=60.00>>60.00 At 30% off, the discount on these books is $60*.30 = $<<60*.30=18.00>>18.00 That mean these 2 books will cost $60-$18 = $<<60-18=42.00>>42.00 He gets 20% off any book under $20 and he buys books for $18.00, $12.00 and $10.00 so these books together cost $18 + $12 + $10 = $40.00 at 20% off, the discount on these books is 40*.20 = $8.00 So these 3 books will cost $40 - $8 = $<<40-8=32.00>>32.00 He has spent $42.00 on the two most expensive books, $32.00 on the 3 cheapest books, and also bought a book for $21.00, so his total comes to $42 + $32 + $21 = $<<42+32+21=95.00>>95.00 #### 95 Lawrence worked 8 hours each day on Monday, Tuesday and Friday. He worked 5.5 hours on both Wednesday and Thursday. How many hours would Lawrence work each day if he worked the same number of hours each day? 8 hours * 3 = <<8*3=24>>24 hours 5.5 * 2 = <<5.5*2=11>>11 hours 24 + 11 = <<24+11=35>>35 hours 35/7 = <<35/7=5>>5 hours Lawrence would work 5 hours each of the 7 days in a week. #### 5 Michael wants to lose 10 pounds by June. He lost 3 pounds in March and 4 pounds in April. How much weight does he have to lose in May to meet his goal? In March and April, he lost 3 + 4 = <<3+4=7>>7 pounds. To meet his goal, he needs to lose 10 – 7 = <<10-7=3>>3 pounds. #### 3 In a class of 30 students, the teacher polls the students on their favorite subject. 1/5 of the students like Math, and 1/3 like English. 1/7 of the remaining students like Science. The rest don’t have a favorite subject. How many students don’t have a favorite subject? 30 x 1/5 = <<30*1/5=6>>6 students like Math. 30 x 1/3 = <<30*1/3=10>>10 students like English. So, 6 + 10 = <<6+10=16>>16 students like either Math or English. Thus, 30 - 16 = <<30-16=14>>14 students neither like Math nor English. Since 1/7 of the remaining like Science, therefore 14 x 1/7 = <<14*1/7=2>>2 students like Science. Hence, 14 - 2 = <<14-2=12>>12 students neither likes the 3 subjects. #### 12 Jerry paid off some of his debts. Two months ago, he paid $12 while last month, he paid $3 more. If his debt was $50 in all, how much does he still have to pay? Jerry paid $12 + $3 = $<<12+3=15>>15 last month. He paid a total of $12 + $15 = $<<12+15=27>>27 for two months. Therefore, Jerry still has to pay $50 - $27 = $<<50-27=23>>23. #### 23 Hannah is buying some apples for $5 per kilogram. If she would get a 40% discount on each kilogram of apples, how much would she pay for 10 kilograms of them? A 40% discount on each kilogram of apples would mean the price being 40/100 * 5 = $<<40/100*5=2>>2 smaller. So one kilogram of apples would cost not $5, but 5 - 2 = $<<5-2=3>>3. So for 10 kilograms of apples Hannah would pay 3 * 10 = $<<3*10=30>>30. #### 30 In the last student council election, the winner got 55% of the votes and the loser got the rest. If the school has 2000 students, but only 25% of them voted, how many more votes did the winner get than the loser? 500 students voted because 2000 x .25 = <<2000*.25=500>>500 The loser got 45% of the votes because 100 - 55 = <<100-55=45>>45 The winner got 275 votes because 500 x .55 = <<500*.55=275>>275 The loser got 225 votes because 500 x .45 = <<500*.45=225>>225 The winner got 50 more votes because 275 - 225 = <<275-225=50>>50 #### 50 Genevieve is a computer programmer working on information security software. She has written 4300 lines of code so far. Every 100 lines of code, she debugs the program. If each debugging only finds three errors, and Genevieve fixes the errors each time before proceeding, how many errors has she fixed so far? Genevieve has debugged the program 4300 / 100 = <<4300/100=43>>43 times. Thus, she has fixed 43 * 3 = <<43*3=129>>129 errors so far. #### 129 Mr. Desmond bought three times as many toys for his younger son as he bought for his elder son. If the elder son received 60 toys, how many toys did Mr Desmond buy? The younger son received three times as many toys as the elder son, which is 3*60 = <<3*60=180>>180 toys Since he bought the toys together, he purchased 180+60 = <<180+60=240>>240 toys. #### 240 1/3 of the townspeople have received the full COVID vaccine. 1/3 are immune because they already recovered from COVID. If 1/6 of the townspeople are both vaccinated and already had COVID, what percent of the town is immune in some way? First add the fractions of vaccinated and recovered townspeople: 1/3 + 1/3 = 2/3 Then you need to subtract the fraction that are both vaccinated and recovered, since they were double-counted. To do this, start by converting 2/3 to the same denominator as 1/6: 2/3 * 2/2 = 4/6 Then subtract 1/6 from 4/6: 4/6 - 1/6 = 3/6 Then divide the numerator by the denominator and multiply by 100% to express the answer as a percentage: 3/6 * 100% = 50% #### 50