Sandy's monthly phone bill expense is equal to ten times her age now. In two years, Sandy will be three times as old as Kim. If Kim is currently 10 years old, calculate Sandy's monthly phone bill expense.

If Kim is currently 10 years old, she will be 10+2 =

<<10+2=12>>12 years old in two years. In two years, Sandy will be three times as old as Kim, meaning Sandy will be 3*12 = <<3*12=36>>36 years old. Currently, Sandy is 36-2 = <<36-2=34>>34 years old. If Sandy's monthly phone bill expense is equal to ten times her age now, she pays 10*34 =$<<10*34=340>>340 in phone bill expense #### 340 Nathan planted 5 strawberry plants and 7 tomato plants. He harvested 14 strawberries from each plant and 16 tomatoes from each plant. He then distributed the strawberries and tomatoes into baskets of 7. He sold a basket of strawberries for $9 and a basket of tomatoes for $6. How much money does Nathan make from his harvest? Nathan harvested a total of 5 x 14 = <<5*14=70>>70 strawberries He harvested a total of 7 x 16 = <<7*16=112>>112 tomatoes. He was able to fill 70/7 = <<70/7=10>>10 baskets with strawberries. He was able to fill 112/7 = <<112/7=16>>16 baskets with tomatoes. He made 10 x $9 = $<<10*9=90>>90 from the strawberries. He made 16 x $ 6 = $<<16*6=96>>96 from the tomatoes. All together, he made $90 + $96 = $<<90+96=186>>186 from his harvest. #### 186 Three different 6th grade classes are combining for a square dancing unit. If possible, the teachers would like each male student to partner with a female student for the unit. The first class has 17 males and 13 females, while the second class has 14 males and 18 females, and the third class has 15 males and 17 females. When the classes are combined, how many students will be unable to partner with a student of the opposite gender? Combining the three classes, there are 17 + 14 + 15 = <<17+14+15=46>>46 male students. Similarly, there are 13 + 18 + 17 = <<13+18+17=48>>48 female students. Thus, there are 48-46 = <<48-46=2>>2 students who cannot partner with a student of the opposite gender. #### 2 Wendy spent 25 years as an accountant and 15 years as an accounting manager. If Wendy lived to be 80 years old, what percentage of her life did she spend in an accounting-related job? First find the total number of years Wendy spent in accounting: 25 years + 15 years = <<25+15=40>>40 years Then divide the number of years she spent in accounting by the number of years she lived and multiply by 100% to find the percentage of her life: 40 years / 80 years * 100% = 50% #### 50 For many years, the number of sharks in Pelican Bay has been twice the number of Pelicans in Shark Bite Cove. But today scientists say one-third of the Pelicans in Shark Bite Cove have moved to Pelican Bay. If there are still 60 sharks in Pelican Bay, how many Pelicans remain in Shark Bite Cove? If there are 60 sharks in Pelican Bay, and this number is twice the number of Pelicans that usually live in Shark Bite Cove, then there were 60/2=<<60/2=30>>30 Pelicans in Shark Bite Cove. If one-third of the Pelicans in Shark Bite Cove move to Pelican Bay, then 30/3=<<30/3=10>>10 Pelicans will have moved away. This would leave 30-10=<<30-10=20>>20 Pelican remaining in Shark Bite Cove. #### 20 At the patisserie, a single layer cake slice is $4 and a double layer cake slice is $7. Dusty buys 7 single layer cake slices and 5 double layer cake slices. If he pays with a $100 bill, how much change does he receive? Single layer cake slices cost $4 x 7 = $<<4*7=28>>28. Double layer cake slices cost $7 x 5 = $<<7*5=35>>35. All the cake slices together cost $28 + $35 = $<<28+35=63>>63. He will receive change of $100 - $63 = $<<100-63=37>>37. #### 37 Christina walks 7km to school every day from Monday to Friday. She returns home covering the same distance. Last Friday her mother asked her to pass by her friend, which is another 2km away from the school in the opposite distance from home. How many kilometers did Christina cover that week? One trip to school is 2 * 7 km = <<2*7=14>>14km. In one week, Christina walks 14 km/day * 5 days/week = <<14*5=70>>70km to school. The extra trip to her mum's friend added 2 km * 2 = <<2*2=4>>4km to her travel distance. Her total distance was thus 70 km + 4 km = <<70+4=74>>74 km #### 74 Opal won $100.00 betting on a horse race. She put half of her winnings into savings and bet the other half of her winnings. This time, she made a 60% profit and again, put half of her earnings into savings. How much did she put into her savings? She won $100.00 and put half into savings so she put 100/2 = $<<100/2=50.00>>50.00 into savings She won $100.00 and put $50.00 into savings so that leaves 100-50 = $<<100-50=50.00>>50.00 to bet She bet $50.00 and made a 60% profit so her profit was 50*.60 = $30.00 The total wins in the second bet are 30+50 = $<<30+50=80>>80 She put half of her $80.00 earnings into savings so that's 80/2 = $<<80/2=40.00>>40.00 into savings She put $50.00 into saving from her 1st bet and $40.00 from her second so she has saved 50+40 = $<<50+40=90.00>>90.00 #### 90 Kenia has three times as many rats as Hunter and Elodie has together. If Elodie has 30 rats, 10 rats more than Hunter, calculate the total number of pets the three have together? Since Elodie has 30 rats, Hunter has 30 rats - 10 rats = <<30-10=20>>20 rats. Together, Elodie and Hunter have 20 rats + 30 rats = <<20+30=50>>50 rats. Kenia has three times as many rats as Hunter and Elodie have together, which is 3 * 50 rats = <<3*50=150>>150 rats Together, the three have 150 rats + 50 rats = <<150+50=200>>200 rats. #### 200 Carol has $60 and saves $9 per week. Mike has $90 and saves $3 per week. How many weeks before Carol and Mike both have the same amount of money? Let x = the number of weeks. 60 + 9x = 90 + 3x to set them equal. 9x = 30 + 3x 6x = 30 x = <<5=5>>5 In 5 weeks they will have equal money. #### 5